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Without balancing, do these reactants yield these products?

a) Al(s) + CuSO4(aq) → Cu(s) + Al2(SO4)3(aq)
b) Hg(s) + AlBr3(aq) → Al(s) + HgBr2(aq)
c) Zn(s) + H2SO4 (aq) → H2(s) + ZnSO4(aq)
d) Ca(s) + MgBr2(aq) → Na(s) + CaBr2(aq)
e) Cu(s) + AlCl3 → no reaction
f) Cl2(aq) + NaI(aq) → Na(s) + ClI(aq)
g) NaCl(aq) + I2 → no reaction

2007-05-27 04:30:02 · 2 answers · asked by Arielle 1 in Science & Mathematics Chemistry

sorry, typo for d) replace Na with Mg

2007-05-27 04:40:43 · update #1

2 answers

Well , Mya. For 50/50 chances, you aren't all that bad, with the exception of (d) and (f). Other flubs, hydrogen is a gas. In order:
a- possible
b- probably not
c- any day of the week and twice on Sunday
e- you got it
g- Yes

How do I know these things? I cheat, of course. And you can too. Go to the back of your book and look at the electrochemical series. It lists many redox type equations, and will give you a ROUGH guide as to the tendency of one metal to displace another. It is not perfect, since there are concentration effects (some ionic compounds have limited solubility, and the equations are written for 1 Molar solutions).

2007-05-27 05:06:09 · answer #1 · answered by cattbarf 7 · 1 0

d) is not right
Ca(s) + MgBr2 (aq) >> CaBr2 (aq)+ Mg (s)


If you want I can balance them

2007-05-27 11:35:29 · answer #2 · answered by Non più attiva su answers 7 · 0 1

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