1/x+1/5x=1/5
x1=6
x2=30
2007-05-27 02:58:44
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answer #1
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answered by iyiogrenci 6
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Let x equal one of the numbers. Then it follows that the other number is 5x.
If the sum of their reciprocals is 1/5, the equation would be:
1/x + 1/[5x] = 1/5
5 + 1 = x
6 = x
That makes the two numbers 6, 5(6). OR, simplified,
6, 30.
Let's check:
1/6 + 1/30 =
5/30 + 1/30 =
6/30 = 1/5
2007-05-27 10:02:13
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answer #2
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answered by Puggy 7
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Number=x
5 times a number= 5x
Let the numbers be x and 5x
therefore,
1/x+1/5x=1/5
=>6/5x=1/5
=>5x=30 [by cross-multiplication]
x=6
One number is 6 and the other one is 30
Let's test these 2 numbers:
30 is 5 times than 6.
1/30 + 1/6= 1/5
1/30 + 5/30= 1/5
6/30=1/5
1/5=1/5
the two numbers are 6 and 30.
2007-05-27 11:37:00
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answer #3
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answered by bob 2
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1 and 5
2007-05-27 09:57:46
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answer #4
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answered by shortee 2
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let the numbers are : x and 5x
1/x + 1/5x = 1/ 5 multiply by 5x
5 + 1 = x
x = 6
the numbers are 6 and 30
2007-05-27 13:10:16
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answer #5
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answered by muhamed a 4
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1 & 5, if the sum of reciprocals is 1/5, then the sum would be 5, and one number is 5 times the other it would have to to be 1&5.
2007-05-27 10:02:52
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answer #6
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answered by J-ROD 4
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Let the numbers be x and 5x
therefore,
1/x+1/5x=1/5
=>6/5x=1/5
=>5x=30 [by cross-multiplication]
x=6
One number is 6 and the other one is 30
2007-05-27 10:07:28
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answer #7
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answered by alpha 7
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let numbers be x and y
x = 5y
1 / x + 1 / y = 1 / 5
1 / 5y + 1 / y = 1 / 5
1 + 5 = y
y = 6
x = 30
Numbers are 6 and 30
2007-05-27 13:20:49
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answer #8
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answered by Como 7
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x = 5y // define x in terms of y
1/x + 1/y = 1/5 // set the equlity
1/5y + 1/y = 1/5 // substitute 5y in for x
1/5y + 5/5y = 1/5 // set the bases to be the same
6/5y = 1/5 // cross multiply
5y = 30 // divide
y = 6
x = 30 // sub 6 back into x = 5y
2007-05-27 10:02:51
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answer #9
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answered by cjdevlin 2
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let 1 no be x
other no =5x
acc to ques
1/x+1/5x=1/5
ans
x =6
therefore,
one number=6
other number=5*6=30
2007-05-27 10:24:10
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answer #10
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answered by dhruv 2
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i ll tell u how to solve it in steps:
Let 1 no. be x;
its reciprocal=1/x
the other no. = 5x;
its reciprocal = 1/5x
Hence ATQ(according to question),
1/x + 1/5x = 1/5
Lcm of x and 5x=(5x)x,
5x + x / (5x)x=1/5
6x / (5x)x= 1/5
cross multiplying we get,
(5x)(x)(1)= (5) (6x)
(5x)x=30x
(5x)x / x = 30
hence 5x = 30 (x and x get cut)
x=30/5
x=6
if x=6
then 5x = 5X6 = 30
therefore one no. = 6
and the other no. = 30
2007-05-27 13:18:10
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answer #11
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answered by changing dreams to realities 2
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