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14 answers

1/x+1/5x=1/5

x1=6
x2=30

2007-05-27 02:58:44 · answer #1 · answered by iyiogrenci 6 · 2 0

Let x equal one of the numbers. Then it follows that the other number is 5x.

If the sum of their reciprocals is 1/5, the equation would be:

1/x + 1/[5x] = 1/5

5 + 1 = x
6 = x

That makes the two numbers 6, 5(6). OR, simplified,
6, 30.

Let's check:

1/6 + 1/30 =
5/30 + 1/30 =
6/30 = 1/5

2007-05-27 10:02:13 · answer #2 · answered by Puggy 7 · 1 0

Number=x
5 times a number= 5x
Let the numbers be x and 5x
therefore,
1/x+1/5x=1/5
=>6/5x=1/5
=>5x=30 [by cross-multiplication]
x=6
One number is 6 and the other one is 30

Let's test these 2 numbers:

30 is 5 times than 6.

1/30 + 1/6= 1/5
1/30 + 5/30= 1/5
6/30=1/5
1/5=1/5
the two numbers are 6 and 30.

2007-05-27 11:37:00 · answer #3 · answered by bob 2 · 0 0

1 and 5

2007-05-27 09:57:46 · answer #4 · answered by shortee 2 · 0 3

let the numbers are : x and 5x

1/x + 1/5x = 1/ 5 multiply by 5x
5 + 1 = x
x = 6

the numbers are 6 and 30

2007-05-27 13:10:16 · answer #5 · answered by muhamed a 4 · 0 0

1 & 5, if the sum of reciprocals is 1/5, then the sum would be 5, and one number is 5 times the other it would have to to be 1&5.

2007-05-27 10:02:52 · answer #6 · answered by J-ROD 4 · 0 2

Let the numbers be x and 5x
therefore,
1/x+1/5x=1/5
=>6/5x=1/5
=>5x=30 [by cross-multiplication]
x=6
One number is 6 and the other one is 30

2007-05-27 10:07:28 · answer #7 · answered by alpha 7 · 2 0

let numbers be x and y
x = 5y
1 / x + 1 / y = 1 / 5
1 / 5y + 1 / y = 1 / 5
1 + 5 = y
y = 6
x = 30
Numbers are 6 and 30

2007-05-27 13:20:49 · answer #8 · answered by Como 7 · 0 0

x = 5y // define x in terms of y

1/x + 1/y = 1/5 // set the equlity

1/5y + 1/y = 1/5 // substitute 5y in for x
1/5y + 5/5y = 1/5 // set the bases to be the same
6/5y = 1/5 // cross multiply
5y = 30 // divide

y = 6
x = 30 // sub 6 back into x = 5y

2007-05-27 10:02:51 · answer #9 · answered by cjdevlin 2 · 2 0

let 1 no be x
other no =5x
acc to ques
1/x+1/5x=1/5

ans
x =6

therefore,
one number=6
other number=5*6=30

2007-05-27 10:24:10 · answer #10 · answered by dhruv 2 · 1 0

i ll tell u how to solve it in steps:
Let 1 no. be x;
its reciprocal=1/x
the other no. = 5x;
its reciprocal = 1/5x
Hence ATQ(according to question),
1/x + 1/5x = 1/5
Lcm of x and 5x=(5x)x,
5x + x / (5x)x=1/5
6x / (5x)x= 1/5
cross multiplying we get,
(5x)(x)(1)= (5) (6x)
(5x)x=30x
(5x)x / x = 30
hence 5x = 30 (x and x get cut)
x=30/5
x=6
if x=6
then 5x = 5X6 = 30
therefore one no. = 6
and the other no. = 30

2007-05-27 13:18:10 · answer #11 · answered by changing dreams to realities 2 · 0 0

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