2007-05-27 01:27:20 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Prime factorisation of 1800 is
(2^3)(3^2)(5^2)
Sum of all the factors is
(2^0+2^1+2^2+2^3)(3^0+3^1+3^2) (5^0+5^1+5^2)
= 15*13*31=6045
2007-05-27 22:42:20 · answer #1 · answered by bharat m 3 · 0⤊ 0⤋
1800 X 1 = 180 X 10 X 1 = 18 X 10 X 10 = 9 X 2 X 5 X 2 X 5 X2 X 1
Sum of the factors = 9 + 2 + 5 + 2 + 5 + 2 + 1 = 26
2007-05-27 01:38:59 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
If you are talking about prime factors:
1800 = 2^3*3^2*5^2
then the sum is:
S = 2+2+2+3+3+5+5 = 22
2007-05-27 01:39:03 · answer #3 · answered by Jess 2 · 0⤊ 0⤋
22
The factors are 2,2,2,3,3,5,5,
2007-05-27 01:39:47 · answer #4 · answered by BettyBoop 5 · 0⤊ 0⤋
infinity
2007-05-27 01:30:45 · answer #5 · answered by Anonymous · 2⤊ 1⤋