stoichiometric question,,?

Question

2 HCl + Na2SO4 --> 2 NaCl + H2SO4

If you start with 20 grams of hydrochloric acid, how many grams of sulfuric acid will be produced?

and plss give me all the steps to the answer too,,

Answer 1

okay, i'll explain it ^_^


The answer is 26.85 grams of sulfuric acid (H2SO4).
This is how you do it:
(20gHCl) x (1mol HCl/36.5g of HCl) x (1mol H2SO4/2mol HCl) x (98gH2SO4/1mol H2SO4) = 26.85 g H2SO4

1)So you start off with 20 g of HCl and you have to convert it to moles. You do that by dividing 20g by 35.5g (the mass of HCl since H is 1 and Cl is 35.5. You look at the periodic table for the mass)
2)Then for every 2 moles of HCl, you get 1 mole of H2SO4 (you get that by looking at the balanced equation.) and so the expression for that is [1mol H2SO4/2mol HCl] and you multiply moles of HCl with that expression.
3) For every mole of H2SO4, you have 98g (H=1, O=16, S= 32. H2SO4=98) so you multiply by 98g.
4) All units should cancel out except grams of H2SO4 and you have your answer.

hope i helped you friend ^_^

Answer 2

The answer is 26.85 grams of sulfuric acid (H2SO4).
This is how you do it:
(20gHCl) x (1mol HCl/36.5g of HCl) x (1mol H2SO4/2mol HCl) x (98gH2SO4/1mol H2SO4) = 26.85 g H2SO4

1)So you start off with 20 g of HCl and you have to convert it to moles. You do that by dividing 20g by 35.5g (the mass of HCl since H is 1 and Cl is 35.5. You look at the periodic table for the mass)
2)Then for every 2 moles of HCl, you get 1 mole of H2SO4 (you get that by looking at the balanced equation.) and so the expression for that is [1mol H2SO4/2mol HCl] and you multiply moles of HCl with that expression.
3) For every mole of H2SO4, you have 98g (H=1, O=16, S= 32. H2SO4=98) so you multiply by 98g.
4) All units should cancel out except grams of H2SO4 and you have your answer.

Answer 3

20/72.9 = x/(2 + 32 + 64)
x = 26.886 g H2SO4
IFF there were more than 119 g NaSO4 present