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f(x) = xe^-x
f'(x) = - xe^-x + e^-x
f''(x) = xe^-x - 2e^-x
- xe^-x + e^-x = 0
e^-x(1 - x) = 0
x = 1

Checking f''(x)
xe^-x - 2e^-x = 0
e^-x(x - 2) = 0
x = 2 for change of inflection
for x < 2 inflection is negative, so slope is decreasing, so the critical point is a maximum.

2007-05-26 12:20:07 · answer #1 · answered by Helmut 7 · 1 0

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