x^2+x=0 Solve for x?

Question

I can't seem to solve this question, it's obvious it can = 0 but is there another answer?

Answer 1

First: factor the expression - find the least common factor.

x^2 + x = 0

x(x + 1) = 0

Sec: solve the "x" variables..

1. x = 0

2. x + 1 = 0 > subtract 1 from both sides (when you move a term to the opposite side, always use the opposite sign).

x + 1 - 1 = 0 - 1
x = 0 - 1
x = - 1

Solution: 0, -1

Answer 2

x^2+x=0

x ( x + 1 ) = 0

x = 0 and x + 1 = 0
x = - 1

x=0 and -1

Answer 3

x=0

Answer 4

X^2+x=0
x(x+1)=0
x=0,-1answers

Answer 5

Yes there is another answer.

x^2+x=0 is a quadratic equation, that means there are two values for x.

if you factor out the x, you'll get

x(x+1)=0

since this is multiplication, and the product is given as 0, one of the factors is 0, too

so it's either

x=0

or the other

x+1=0 a.k.a. x=-1

Hope, I helped.

Answer 6

x^2+x=0

x(x+1)=0

x+1=0 or x=0#
x=-1#

Answer 7

x(X+1)=0 . ... this quadratic equation x hav 2 possible answer
for x=0, true
for x+1=0 , x= -1 true

good luck to try understand the concept of quadratic

Answer 8

x^2 + x = 0
(-1)^2 + (-1) = 0

so,
x = -1

Answer 9

it is only 0

just plug in some numbers and see the pattern

x = 1
1^2 + 1 = 3

x = 2
2^2 +2 = 6

x = 3
3^2 + 3 = 12

as you can see the numbers get bigger as x increases

x = -1
-1^2 + (-1) = 1

x = -2
-2^2 + (-2) = 2

x = 3
-3^2 + (-3) = 6

x also gets bigger as the numbers get smaller

Answer 10

use the formula (-b +/- sqrt(b^2-4ac))/2a

(-1 + sqrt(1-0))/2 = 0/2 = 0

(-1 - sqrt(1-0))/2 = -2/2 = -1

these are the zeros of your function: 0 and -1


byebye!!!