2007-05-26 09:04:06 · 5 answers · asked by gisappy 1 in Science & Mathematics ➔ Mathematics
I need 3 unique quadratic equations
2007-05-26 09:05:08 · update #1
1) x^2 - 5x + 6 = 0
a = 1 , b = -5 , c = 6
discriminant = b^2 - 4ac = ( -5)^2 -4x1x6
= 25 - 24 = 1 positive
2) x^2 -4x + 4 = 0
a = 1 , b = - 4 , c = 4
discriminant = b^2 - 4ac =(-4)^2 -4 x 1 x 4
= 16-16 = 0
3) x^2 +2x + 7 = 0
a = 1 b = 2 c = 7
discriminant = b^2 - 4ac =( 2)^2 - 4x1x7
= 4-28 = -2 4 negative
2007-05-26 10:50:54 · answer #1 · answered by muhamed a 4 · 0⤊ 0⤋
Discriminant = b^2 - 4ac
positive:
b^2 > 4ac
zero:
b^2 = 4ac
negative:
b^2 < 4ac
2007-05-26 17:04:15 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
x^2-4x-2=0
discriminant=16+8=24>0
x^2+6x+9=0
discriminant=36-36=0
x^2+6x+10=0
discriminant=36-40=-4 <0
2007-05-26 16:20:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
http://www.mathworld.wolfram.com
2007-05-26 16:10:04 · answer #4 · answered by Anonymous · 0⤊ 0⤋
No, I don't think I will. Thanks for offering however.
2007-05-26 16:07:40 · answer #5 · answered by Anonymous · 0⤊ 0⤋