Super Math Question 2! Will Reveal Second part to Secret of Reality! Up for it?

Question

Solve:

x2 + y2 = 100
y2 = x+10


(I couldn't make the 2's to squares, so pretend the 2's after the variables are squares. EX: x2 = x sqaured.)

Caution: there are more than one solution. Name them all. (Hint: they're three, and they are in ordered pairs.)

Solve this one and I'll tell you a vital piece of the Secret of Reality.

Answer 1

x^2+x+10=100
x^2+x-90 = 0
(x+10)(x-9) = 0
So x = 9 and x = -10
When x = -10, y =0
When x = 9, y = +/- sqrt(100-81)=sqrt(19)
Thus the three solutions are;
(-10, 0), (9, sqrt(19)), and (9, -sqrt(19))

This is the intersection of a circle and a parabola where the vertex of the parabola is tangent to the circle at (-10,0).

Answer 2

x2 + x + 10 = 100
x2 + x - 90 = 0
(x + 10) * (x - 9) = 0

y2 = x + 10 -->

y2 = 19
or
y2 = 0

x = 9, y = sqrt(19)
x = 9, y = -sqrt(19)
x = -10, y = 0
.

Answer 3

From the given equation x= x(16x-a million) if x = 0. equation is happy & consequently x= 0 is a answer. if x no longer equivalent to 0, then cancelling x on the two part a million= sixteen x-a million or 16x = 2 x = 2/sixteen = a million/8

Answer 4

x^2 + x + 10 = 100

x^2 + x - 90 = 100

x = [-1 +/- sqrt(1-4*1*-90)]/2 = (-1 +/- sqrt 361)/2 = (-1 +/- 19)/2

= -10 or 9

(-10, 0) (9, sqrt 19) (9, -sqrt 19)

Answer 5

x2 +y2=100
y2=x+10

so x2+x+10=100
or,x2+x-90=0
or,x2+10x-9x-90=0
or,x(x+10)-9(x+10)=0
or,(x+10)(x-9)=0

so either x= -10
or,x=9
and y=either {100-(-10^2)
=0
or y=(100-9^2)
=19^0.5.

Hope it'll help u.

Answer 6

first pair: x=9, y=4.35889894354
Second Piar: x=9, y=-4.35889894354
Third Pair: x=-10, y=0

Anything else you need help with?

Answer 7

x = -10,+9

y=0,+/-4.358

Answer 8

Dream on. And a good week-end to you.

Answer 9

Huh?