I need help on these problems. What i dont understand is that why do you sometimes leave the two fractions being multiplied?
And can someone explain to me how its done in the book it said that its the reverse of multipling so wouldnt that be dividindg?
Well Thanks for the help!!!
1. 3/4t=
2. 11/12x=
3.x-3/4=
4. 5/7(4x-1)
5. 10/2x+1=
2007-05-26 05:59:33 · 4 answers · asked by Kuro 1 in Science & Mathematics ➔ Mathematics
I think I know what you want, and that’s expressing these in a different form.
In that case, I’ll do the first one by steps, then just do the rest.
1.3/4t=(3/4)t=(3/4)(t/1)
With me so far (t/1) is just t, because anything divided by one remains unchanged.
Now as with the multiplication of any two fractions you multiply the numerators, the top, or in this case the left, by the top, again in this case the left.
Then the bottoms, the denominators, in this case the right, giving.
(3t)/(4) or 3t/4, now maybe you see how it is dividing, at least I hope you do, leaving out the explanation.
3/4t=3t/4
2.11/12x=11x/12
3.x-3/4 can’t do this one that way, but you could do this, but it may be too advanced for you, no offense.
x-3/4=[(x-3/4)(x)]/(x)=(x^2 -3/4x)/x
4.5/7(4x-1)=(5/7)[(4x-1)/1]=[5(4x-1)]/[(7)(1)]=(20x-5)/7
5.10/2x+1=10x/2+1, but could also be just 5x=1
Hope this lengthy but complete answer helps.
Doug
Ps: Hint: It wouldn’t hurt if you spellchecked your questions, or your answers on homework, I do.
2007-05-26 07:03:14 · answer #1 · answered by DOUGLAS M 6 · 0⤊ 0⤋
Well 1, 2, and 3 seem to be simplified already. 4) can be written as 20/7x - 5/7 and 5) can be written as 5x + 10
2007-05-26 13:05:09 · answer #2 · answered by Lady Geologist 7 · 0⤊ 0⤋
Division is nothing but reciprocal multiplication. As for the sums you can very well ask your sir.
2007-05-26 13:11:08 · answer #3 · answered by tta r 1 · 0⤊ 0⤋
Uhhh the 1st answer is...oops homework bell rung..sry
2007-05-26 13:02:50 · answer #4 · answered by Anonymous · 0⤊ 0⤋