algebra can anyone figure this one out?

Question

Factor this polynomial 9a^4b^6c^4 -4d^6 can anyone help with this, I think the amswer is (3a^2b^3c^2)(3a^2 b^3c^2 -2d^3) but I am really confused on this one any help would be appreciated

Answer 1

9a^4b^6c^4=(3a^2 b^3c^2)^2
4d^6=(2d^3)^2
so
answer is
(3a^2 b^3c^2-2d^3)(3a^2 b^3c^2+2d^3)

Answer 2

This is simply the differencec of two squares:
(3a^2b^3c^2-2d^3)(3a^2b^3c^2+2d^3)

Answer 3

(a+b)(a-b)=a^2-b^2

so

(3a^2b^3c^2+2d^3)(3a^2b^3c^2 -2d^3)= 9a^4b^6c^4 -4d^6

Answer 4

ok, you recognize you are confused. WHAT are you confused about?
Im confused also. you could easily factor this polynomial this way :
(1)(9a^4b^6c^4-4d^6) and thats much simpler and nothing is false about it at all. So why not factor it that way?

Answer 5

9a^4b^6c^4 -4d^6
=(3a^2)(2b^^3)^2(c^2)^2-2d^3)^2



(6a^2b^3c^2)^2)-(2d^3)^2
(6a^2b^3c^2+2d^3)(6a^2b^3c^2-2d^3).
your answer is right.

Answer 6

9(a^4)(b^6)(c^4) -(4d^6) has no common factors.

Answer 7

That math is useless