what is the antiderivative of -sin(2x)?

1 ⤊

2007-05-26 05:07:09 · 4 answers · asked by Olivia G 1 in Science & Mathematics ➔ Mathematics

cos(2x)/2

2007-05-26 05:10:26 · answer #1 · answered by bruinfan 7 · 1⤊ 0⤋

I = - â«sin (2x).dx
let u = 2x
du/dx = 2
dx = du / 2
I = (- 1/2).â«sin u du
I = (1/2) cos u + C
I = (1/2).cos 2x + C

2007-05-26 13:06:29 · answer #2 · answered by Como 7 · 0⤊ 0⤋

INTEGRAL[ -sin(2x)dx ] =
INTEGRAL[ (1/2)(-1)sin(2x)2dx ]=
(1/2)(cos(2x)) + C

2007-05-26 12:11:55 · answer #3 · answered by fcas80 7 · 0⤊ 0⤋

1/2cos2x.

2007-05-26 12:11:44 · answer #4 · answered by Anonymous · 0⤊ 0⤋