The sum of two numbers is 37. Their difference is 7. What are the two numbers?

Question

okay i know the answer is 15 and 22 but i am not sure how to write it out in algbera way can any one help. yep been up all night working on this checkpoint.

Answer 1

Algebraic Expressions:
1. x + y = 37
2. x - y = 7

*Solve the "x" or "y" variable in either equation. Let's solve/isolate the "x" variable in the 1st equation.

First: subtract "y" from both sides (when you move a term to the opposite side, always use the opposite sign).

x + y - y = 37 - y
x = 37 - y

Sec: replace/substitute "37-y" with the "x" variable in the 2nd equation.

(37 - y) - y = 7
37 - y - y = 7
37 - 2y = 7

Third: combine "like" terms - subtract 37 from both sides.

37 - 37 - 2y = 7 - 37
- 2y = 7-37
- 2y = -30

*Divide both sides by -2.

- 2y/-2 = -30/-2
y = 30/2
y = 15

Fourth: replace 15 with the "y" variable in the 1st equation.

x + 15 = 37 > subtract from both sides.
x + 15-15 = 37-15
x = 37-15
x = 22

Solution (22, 15)

Answer 2

Let the numbers be x and x + 7

'We take x and x + 7 as the unknown numbers as it is stated that the difference between them is 7 and hence one number must be 7 more than the other

x + x + 7 = 37
2x + 7 = 37
2x = 30
x = 15

x + 7 = 22

15 and 22 are the numbers.

P.S: You can use the x + y, x - y method, but that'll take more steps.

Answer 3

To solve this question,
let X be the smaller number
the larger number is X + 7

X + (X+7) = 37
2X + 7 = 37
(Subtract 7 from both sides)
2X = 30
(divide each side by two)
X = 15
X + 7 = 22

Answer 4

each accurate of the type 4n+a million is the sum of two squares yet no accurate of the type 4n+3 might want to be expressed because the sum of two squares. This theorem become first stated with the help of Fermat and the first printed information become with the help of Euler. this is extremely elementary to instruct employing the mathematics of the Gaussian integers. employing this theorem it really is elementary to discover examples of a number of consecutive primes which aren't to any extent further the sums of two squares - you in basic terms search for a run in which each and each of the primes are of the type 4n+3.

Answer 5

Hey look,u can simply answer this question by writing 2 equations and solving them simultaneously as follows:
x+y=37
x-y=7 (the ys are crossed out with each other)

2x=44
x=22
then substitute your x value in either of the 2 equations:
22+y=37
y=15

so the 2 no. are 22 and 15!!

hope this helps!!!!! :-)

Answer 6

x + y = 37
x - y = 7

Solving for x in one equation:

x + y = 37
x = 37 - y

Substitute that for X in the second equation:

(37 - y) - y = 7

Solve for Y:

37 - y - y = 7
37 -2y = 7
-2y = 7 - 37
-2y = -30
y = -30/-2
y = 15

Substitute it for Y in either of the original equations:

x + y = 37
x + 15 = 37
x = 37 - 15
x = 22

Answer 7

Let the smaller number be x
And the bigger number be (x+7)

x + (x+7) = 37
2x = 37 - 7
2x = 30
x = 15

Answer 8

SIMUTANEOUS EQUATIONS (remember this term)

So,
x+y = 37
x = y+7
Subsitute the second equation into the first.
y+7+y=37
2y = 30
y=15.
If y = 15, x = 15+7 = 22

Never ever guess!

Answer 9

see the let one number be x
therefore the second number is x+7 or x-7
takingthe two numbers as x and x+7we find that
(x)+(x+7)=37
2x+7=37
2x=37-7
2x=30
x=30/2
x=15

so one no is 15 and the other no is 15+7=22

Answer 10

let numbers be x and y.
x + y = 37
x - y = 7------ADD
2x = 44
x = 22
y = 15