whats the formula of a triangle?

Answer 1

Area of triangle = (1/2) * base * corresponding altitude

Perimeter = Sum of the sides

Area of equilateral triangle = [(side)^2 * sqrt 3]/4

There's another formula for area of triangle. It is called Hero's formula.

Let a triangle have sides x, y and z

Take half the perimeter:
(x + y + z)/2 = s

s is called the semi perimeter (meaning half the perimeter)

Area of the triangle :
sqrt [s(s - a)(s - b)(s - c)]


Pythagoras theorem:
In a right triangle, the sum of the squares of the legs = the square of the hypotenuse.

Let x, y be the legs and z be the hypotenuse. Then:
x^2 + y^2 = z^2


In an isosceles right triangle, the hypotenuse is length of a leg multiplied by sqrt 2

Let x, y be the legs and z be the hypotenuse. x = y
Then z = x * sqrt 2

Answer 2

I'm going to assume you mean the formula for AREA of a triangle. It's 1/2 length * height.

If you meant the formula for the length of the side of a right triangle, it's a^2 + b^2 = c^2,

where c is the length of the longest side and a and b are the two shorter sides. There are MANY MANY other formulas involving triangles, look in any math textbook for examples.

Answer 3

For right triangle, a^2 + b^2 = c^2

a & b = legs/short

For all,

A=1/2 x B x H

**NOTE:** ^2 = squared

Answer 4

Area = 1/2 * base * height

Answer 5

Area of a traingle=1/2*(b*h)
Perimeter of a traingle=2(l+b)

Answer 6

1/2 * height * base length = area

Answer 7

what forumula are you talking about?

Area = 1/2 bh

pythagorean theorem... a^2 + b^2 = c^2

all interior angles must add up to 180 degrees.

Answer 8

ds^2 = g11dx^2 + (g12 + g21)dxdy + g22dy^2,

where gij are the metric components (usually g12 = g21).

Answer 9

a=1/2(w*h)

there are others too... i am confused on what you are asking for...