x(x+1)(x-1)
is the answer x^2-x
x^-2x^2 +x
or 3x-1
please help me!!
2007-05-25 15:24:37 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x (x + 1) (x - 1)
(x^2 + x ) (x - 1)
x^3 - x^2 + x^2 - x
x^3 - x
2007-05-25 15:29:00 · answer #1 · answered by 7 · 0⤊ 0⤋
x(x+1)(x-1)=
x(x^2-1)=
x^3-x
2007-05-25 22:32:12 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It's easy if you recognize that (x+1)(x-1) = x² - 1, the difference of two perfect squares. Then you can simply multiply x² -1 by x to obtain x³ - x.
Remember, for any two numbers a and b, the product of their sum and difference, (a + b)(a - b), yields the difference of their squares, a² - b².
a + b
a - b
---------------
a² + ab - ab - b² = a² - b²
2007-05-25 22:39:58 · answer #3 · answered by MathBioMajor 7 · 0⤊ 0⤋
x^3-x
2007-05-29 06:27:31 · answer #4 · answered by Memoirs of a Tricia 1 · 0⤊ 0⤋
X(X+1)= 1x+1x then 1x+1x(1x-1) 1x+1x+1x-1x=3x
2007-05-25 22:32:19 · answer #5 · answered by jellybeanqueen 3 · 0⤊ 0⤋