Subtract 3x from both sides. You now have: 3(x - 5) = x + 5. Distribute the 3 to get 3x - 15 = x + 5. Subtract x from both sides and add 15 to both sides to come up with 2x = 20. Divide by 2 to end up with x = 10.
2007-05-25 14:15:10
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answer #1
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answered by sillysalamander101 2
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The first thing you want to do is multiply the parentheses to get {3x - 15 + 3x = 4x + 5 }. Then you want to get the x's by themselves and then normal numbers on the other side. which if you add {3x + 3x - 4} it equals 2x. And on the other side you would get {5 + 15} equals 20. so now your equation looks like this {2x = 20}. And 2 multiplied by 5 = 10
Your answer is: 10
2007-05-25 14:49:50
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answer #2
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answered by Jesus Freak 2
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x= 10
2007-05-25 14:11:42
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answer #3
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answered by BandNerd 2
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x=10
2007-05-25 16:37:04
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answer #4
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answered by doug_johnson39 2
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3 (x-5) + 3x = 4x + 5
multiply (x-5) by 3
3x-15 +3x = 4x + 5
add like terms
6x - 15 = 4x + 5
subtract 4x on both sides
2x - 15 = 5
add 15 to both sides
2x = 20
divide 2 into 20
x= 10
2007-05-25 14:18:42
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answer #5
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answered by Miriam180 2
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3(x-5) +3x = 4x + 5
Simplify by using the distributive property in the parentheses:
3x - 15 + 3x = 4x + 5
Combine the 3x and 3x:
6x - 15 = 4x + 5
Subtract 4x from both sides:
2x - 15 = 5
Add 15 to each side:
2x = 20
Divide by 2:
x = 10!
2007-05-25 14:16:03
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answer #6
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answered by wannalala 3
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x=10
2007-05-25 14:12:59
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answer #7
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answered by cadcd26 1
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x=10
2007-05-25 14:11:52
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answer #8
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answered by Anonymous
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USE YOUR GRAPHING CALCULATOR!
You can go to Y=and type 3(x – 5) + 3x
go to the second Yand type=4x + 5
Next, go to 2nd (yellow key usually) and press graph. Look at the table. If the two Y columns have the same number, (any number but they must be the same) The value under the x is the answer.
2007-05-25 16:34:31
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answer #9
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answered by stacy 1
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3x-3*5=3x-15------------1
ie3x-15+3x=4x+5
add x values in left side,so 6x-15
6x-15=4x+5
now bring the x values together on any side but be careful in signs(+ or -)
6x-4x=5+15
2x=20
so x=? 20/2 =10 (solved)
Now u can also cross check ur answer by applying the x value in the question.
2007-05-25 14:49:35
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answer #10
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answered by rubynama 2
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