2007-05-25 12:49:43 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Reflecting across the y-axis negates the x's. So you have
g(x) = f(-x) = 2(-x)^3 - 6(-x)² - 7(-x) - 3
g(x) = -2x^3 - 6x² + 7x - 3
2007-05-25 12:57:03 · answer #1 · answered by Kathleen K 7 · 0⤊ 0⤋
To reflect a function across the y-axis, just substutite (-x) in for x. So, the reflection would be 5(-x)^2 + 7(-x)^2 + 4(-x) - 5 = -5x^3 + 7x^2 - 4x - 5.
2016-05-17 23:15:05 · answer #2 · answered by leann 4 · 0⤊ 0⤋
g(x)= 2(-x)^3-(-x)^2--7(-x)-3 I'm not sure what that
-x6^2 in you equation is all about, but just go through and replace all the x's with -x's.
Doug
2007-05-25 12:57:20 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
f(x) = -2x^3 -6x^2 +7x -3
2007-05-25 13:11:21 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
reflect across x: f(-x)
reflect across y: -f(x)
2007-05-25 13:51:40 · answer #5 · answered by kidwithshirt 2 · 0⤊ 0⤋