discrete math functions problem?

Question

Let f(n) = lg(n) be the log 2 function. Find f(2048).

Answer 1

you are just looking for the value of log_2 (2048). Since 2^11 = 2048, then log_2 (2048) = 11

Answer 2

lg 2048 = 11

It would probably be a good idea for you to memorize the first few powers of 2:

2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=128
2^8=256
2^9=512
2^10=1024
2^11=2048
2^12=4096
2^13=8192
2^14=16,384
2^15=32,768
2^16=65,536
2^17=131,072
2^18=262,144
2^19=524,288
2^20=1,048,576

Answer 3

That is easy because 2048 = 2^20

And f(2048) = lg(2^20) = 20lg(2)=20(1) = 20

Answer 4

remember the fog(x) or f(g(x)) notation, dude? this is in certainty fixing for the fee of f(x) whilst x=g(x). think of of it this variety. permit f(x)=x+2. as quickly as we are asked to unravel for f(2), we replace 2 with x, subsequently-> f(2)=2+2=4. Composition of applications issues -> comparable technique. even however, fairly of numbers, we are comparing with expressions. a. f(x) = x +2 f(f(x)) = (x+2) + 2 changing x with f(x), or x+2 f(f(x)) = x + 4 b. f(x) = 3x f(f(x)) = 3(3x) f(f(x)) = 9x changing x with f(x) that's 3x Bro, i think of you have a typo in merchandise c. i'm hoping this permits.