(3x^4 y^7)^2
2007-05-25 12:21:55 · 15 answers · asked by chanel w 1 in Science & Mathematics ➔ Mathematics
(3x^4*y^7)^2
= (3x^4)^2 * (y^7)^2
= 9x^8 * y^14
= 9x^8 y^14
2007-05-27 03:08:14 · answer #1 · answered by wangsacl 4 · 0⤊ 0⤋
Every number or variable is squared
So 3^2x^4*2 y^7*2 = 9x^8 y^14
2007-05-25 12:46:26 · answer #2 · answered by KG 3 · 0⤊ 2⤋
9x^8 y^14
Easy
2007-05-25 12:28:12 · answer #3 · answered by parikhgators 1 · 1⤊ 1⤋
when you have exponents within parentheses, and the term is raised to another power, multiply the coefficients and the exponents:
3^2=9
(x^4)^2=x^8
(y^7)^2=y^14
so it's 9x^8y^14
2007-05-25 12:40:10 · answer #4 · answered by Anonymous · 1⤊ 2⤋
9x^8y^14
Easiest 10 points ever.
edited to add -- you know, next time, try asking how to do the problems and telling us what you don't understand about them. That way, you can learn how to do the problems yourself instead of just having other people do them for you.
2007-05-25 12:25:14 · answer #5 · answered by Pascal 7 · 3⤊ 2⤋
9x^8 y^14
2007-05-25 12:31:21 · answer #6 · answered by Julie 1 · 1⤊ 1⤋
9x^8 y^14
2007-05-25 12:31:03 · answer #7 · answered by Anonymous · 1⤊ 1⤋
9x^8 y^14
2007-05-25 12:25:28 · answer #8 · answered by ? 5 · 1⤊ 1⤋
(3x^4y^7)^2 = 9x^8y^14
Now so you'll understand it:
(3x^4y^7)^2=(3x^4y^7)(3x^4y^7)=
(3xxxxyyyyyyy)(3xxxxyyyyyyy)
Now 3x3 = 9 and for the rest just count.
2007-05-25 12:39:02 · answer #9 · answered by cicero 2 · 1⤊ 2⤋
9x^8y^14
2007-05-25 20:51:53 · answer #10 · answered by shiva 3 · 0⤊ 1⤋