The ordered pair ( 1,?)
2007-05-25 10:51:22 · 13 answers · asked by Monique L 2 in Education & Reference ➔ Homework Help
2x + 3y = 8
substitute 1 for x
2(1) + 3y = 8
that would be...
2 + 3y = 8
subtract 2 from both sides
2 + 3y = 8
-2 -2
that equals...
3y = 6
divide by 3
y = 2
ordered pair would be...
(1,2)
2007-05-25 15:49:12 · answer #1 · answered by Jasmeen 3 · 0⤊ 0⤋
Ok, well...
2(1) + 3y = 8 Add in the one
2 + 3y = 8 Multiply 2 and 1
2 - 2 + 3y = 8 - 2 Subtract 2 from each side
3y = 6 Divide each side by 3
y = 2
(1,2)
2007-05-25 11:01:25 · answer #2 · answered by Alyssa 3 · 0⤊ 0⤋
2
2007-05-25 10:55:42 · answer #3 · answered by jjo 2 · 0⤊ 0⤋
In order to find independent values for x and y there must be 2 equations. With just a single equation you can express one of the variables (x,y) in terms of the other. For example, y = (8 - 2x)/3. If the ordered pair (1,?) assigns the value 1 to x and requires a solution for y, then y = (8 - 2)/3 = 2.
2007-05-25 13:01:13 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Substitute 1 for x:
2(1) + 3y = 8
Simplify:
2 + 3y = 8
Subtract 2:
3y = 6
Divide by 3:
y = 2, so (1,2) is your final answer.
2007-05-25 14:06:35 · answer #5 · answered by wannalala 3 · 0⤊ 0⤋
If x=1 then y=2
2(1)+3y=8
2+3y=8
2-2+3y=8-2
3y=6
y=2
2007-05-25 13:13:48 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
2x+3y=8; x=1
2+3y=8
3y=6
y=2 x,y
Ordered Pair (1,2)
2007-05-25 11:00:51 · answer #7 · answered by Joseph R 2 · 0⤊ 0⤋
2(1)+3y=8
3y=8-2
3y=6
divide by 3 both sides
y=2
2+6=8
2007-05-25 14:41:51 · answer #8 · answered by stemo 3 · 0⤊ 0⤋
2(1) + 3y = 8
2 + 3y = 8
3y = 8-2
3y=6
y=2
2007-05-25 10:55:32 · answer #9 · answered by j c 2 · 2⤊ 0⤋
2x + 3y = 8, x=1
2(1) + 3y = 8
2 + 3y = 8
3y = 8-2 (transposition)
3y = 6
y = 6/3
y = 2
pair is (1,2)
2007-05-25 11:06:25 · answer #10 · answered by hmeph 1 · 0⤊ 0⤋