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thereof. Write an inequality representing the number of minutes a person could talk without exceeding $6.

2007-05-25 09:57:20 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Let x = total duration of call in minutes
1.11 + 0.97 (x - 1) ≤ 6
0.97 x + 1.11 - 0.97 ≤ 6
0.97 x + 0.14 ≤ 6
0.97 x ≤ 6.14
x ≤ 6.14 / 0.97
x ≤ 6.33 mins
Could talk for 6 min 20 sec or 6 min (to nearest min.)

2007-05-26 00:18:47 · answer #1 · answered by Como 7 · 0 0

The man is so out of it for talking for such exhoritant rates. If X = the number of minutes spoken, Let Y= int(X-1) and
0.97 * Y < 4.89

2007-05-25 17:09:06 · answer #2 · answered by cattbarf 7 · 0 0

x = number of minutes used

1.11 + (0.97)(x - 1) <= 6

2007-05-25 17:01:41 · answer #3 · answered by Mathematica 7 · 1 0

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