How to draw 2 different possible Lewis Structures for butene?
2007-05-25 09:46:57 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
You could have 2 major Lewis structures, one with the double bond at the end (between carbons 1 and 2), and one with the double bond right in the middle. The formula would be C4H8 (Index of hydrogen deficiency therefore =1).
The combustion formula is:
C4H8 + 6O2 ----> 4CO2 + 4H2O
2007-05-25 09:59:57 · answer #1 · answered by Rick P. 3 · 0⤊ 0⤋
The equation for the combustion of butene is:
C4H8 (g) + 6 O2 (g) --> 4CO2 (g) + 4 H2O (l)
Please note that butEne is C4H8 and butAne is C4H10.
There are various isomers of butene
H2C=CH-CH2-CH3 which is but-1-ene
H3C-CH=CH-CH3 which is but-2-ene
H2C=C (CH3)2 which is actually 2-methyl-prop-1-ene, but which still has the formual C4H8.
Hope this helps.
2007-05-25 09:56:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2 C4H10 + 13 O2 8 CO2 + 10 H2O
2007-05-25 09:53:45 · answer #3 · answered by DanE 7 · 0⤊ 3⤋
C4H8 + 6O2 â 4CO2 + 4H2O
2007-05-25 09:58:42 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋