That doesn't make sense.
2007-05-25 09:04:45
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answer #1
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answered by Anonymous
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Maybe (just maybe), you mean:
The cube root of P squared
that will give you 'a'.
because
a^3 = P^2
Kepler's third law.
In our solar system, if you give the orbital period in Earth years and the distances from the sun in Astronomical Units (the mean distance from the Sun to Earth), then the formula will work.
Of course, for Earth, we get
1^3 = 1^2 which must be true (because 1 raised to any power is 1).
Mercury:
P = 0.2409 Earth year. P squared = 0.058
cube root of 0.058 = 0.38716
Real orbital radius for Mercury = 0.387099
Venus
P = 0.6152; P squared = 0.3785
cube root = 0.72334
Real orbital radius = 0.72333
Saturn
P = 29.498; P squared = 870.132
cube root = 9.54689
real orbit = 9.55753
close enough.
So, if you are given the time (P) it takes for an object to orbit the Sun (in Earth years), then you can find it's average distance (a) from the Sun.
a = cube root of P^2
If you are given the average distance from the Sun, you can find the period of the orbit:
P = square root of a^3
2007-05-25 16:55:40
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answer #2
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answered by Raymond 7
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P ^ 2 cubed would be P ^2*3=P^6
2007-05-25 16:09:41
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answer #3
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answered by Dave aka Spider Monkey 7
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When raising a value with an exponent to an exponent, you multiply the exponents, so (P^3)^2 = P^6
For example if P=2, then (2^3)^2 = 8^2 = 64.
This is the same as 2^6 -- 2*2*2*2*2*2=64.
2007-05-25 16:11:23
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answer #4
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answered by Sir N. Neti 4
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P^3^2= P^6, you simply multiply exponents.
2007-05-25 16:07:37
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answer #5
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answered by WC 7
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if you are simplifying, the answer would be:
p multiplied by the square root of p OR p•âp OR pâp
2007-05-25 16:14:35
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answer #6
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answered by Kasparov 2
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