when you speed up the flow of water in a pipe does the pressure of the water go up?

Question

when you speed up the flow of water in a pipe does the pressure of the water go up

Answer 1

When a pipe with water is static (no flow), there is a static pressure in the pipe that is nearly uniform from entrance to exit.

However, when a nozzle is opened and water begins to flow, then a dynamical pressure exists that is related to the velocity of the flow -- v^2 portion of Bernoulli's equation. You can measure the pressure changes at various cross sectional locations in the pipe to see this effect.

From start to finish, the overall guage pressure decreases from frictional losses with the walls and the viscous nature of all fluids.

However, as long as the fluid continues to move, with no changes in the pipe size, the dynamical pressure is the same from entrance to exit.

So the answer is.. depends on whether you're measuring static or dynamical pressure.

Answer 2

I would think it depends on the opening as well. If the openings too small then "yes" the water pressure would rise. The larger the opening, the less water pressure. I'm pretty sure the water pressure would go up anyways considering more water is being forced into the pipe that's only so big.

Answer 3

Don't think so because if the water in the tap is let to go in a certain speed then the pressure is released.
The pressure inside a tap increases when the water is accumulated in the tap.

Answer 4

It depend on how you do it. If you turn on a pump, the pressure in the output pipe increases. If you open a spigot on a pipe already pressurized, the upstream pressure decreases.

Answer 5

by increasing the velocity of the flow you have increased the volume flow, when the volume of flow increases the pipe friction loss increases and a corresponding increase in pressure is required or a decease in the fluid's viscosity. Presuming that the viscosity remains the same, an increase in pressure would be required to create the increase in flow and ultimately to increase the velocity.

Answer 6

we have bernoullis equation, P+hdg+1/2dv.v=constant P=pressure d=density v=velocity h=height 130kPa+0+1/2(1.6)(1.6)=P+0+1/2(6.4)(6.... P=110.8kPa

Answer 7

No, cite Bernoulli's equation.

As velocity of a fluid increases, pressure decreases