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How many grams of sodium chloride could be produced from the reaction of 10.5g of sodium with 18.6L of chlorine

2007-05-25 06:42:18 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

Na is the limiting reactant.

26.7065 g

2007-05-25 07:49:01 · answer #1 · answered by ag_iitkgp 7 · 1 0

10.5 g / 22.98977 = 0.457 moles Na

to get moles of chlorine you have to give me the molarity.

May be it means at STP

in this case

n = pV / RT = 1 x 18.6 / 0.0821 x 273 = 0.830 moles Cl2

2 Na + Cl2 >> 2NaCl

the ratio is 2 : 1 so Na is the limiting reactant

we get 0.457 moles NaCl

0.457 x 58.44 g/mol = 26.7 g

2007-05-25 14:37:34 · answer #2 · answered by Non più attiva su answers 7 · 0 1

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