Simplify each radical expression... But leave it in radical form... so basically i'm not sure how to simplify it more. Could someone please help?
√300
and
√x^4 yz^6
2007-05-25 06:01:23 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sqrt(300) = sqrt(3 * 10 * 10)
= 10 x sqrt(3)
and
sqrt(x^4 * y * z^6) = sqrt( x^2 * X^2 * y * z^2 * z^2 * z^2)
=x^2 * z^2 * z * sqrt(y)
= x^2 * z^3 * sqrt(y)
2007-05-25 06:13:17 · answer #1 · answered by K In the House 4 · 0⤊ 0⤋
The sqrt(300) would be 10 * sqrt(3) because you can break it into the sqrt(100 * 3) and then the sqrt of 100 is 10 so 10 * sqrt(3).
sqrt(x^4*y*z^6) = x^2 * z^3 * sqrt(y)
2007-05-25 13:08:50 · answer #2 · answered by Cooper 2 · 0⤊ 0⤋
â300
â100 x â3
10â3
âx^4 yz^6
x² y^6 z^6
2007-05-25 13:08:14 · answer #3 · answered by Sunny Grewal 2 · 0⤊ 1⤋
â300 = â(100 x 3) = 10.â3
â(x^4.y.z^6) = x².ây.z³
2007-05-26 04:01:53 · answer #4 · answered by Como 7 · 0⤊ 0⤋
sqrt(300) = sqrt(100)*sqrt(3) = 10sqrt(3)
sqrt(x^4yz^6) = sqrt(x^4)*sqrt(y)*sqrt(z^6) = x^2z^3sqrt(y)
2007-05-25 13:08:41 · answer #5 · answered by T 5 · 0⤊ 0⤋