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11 answers

Atlas used to know give or take the odd kilo, but given the added population and extensive building since he used to use it as a weight training aid, he may be a bit off the mark.

2007-05-26 10:15:34 · answer #1 · answered by Dava 4 · 0 0

I assume this planet means Earth. It is weightless since it is orbiting the Sun, just like the astronauts are weightless when they are orbiting the Earth. To calculate Earth's mass, then the weight of a known mass combined with the known radius of the Earth is enough to calculate the Earth's mass using the equation F=GMm/R^2, where F is the weight of the 1kg mass (measured in Newtons, because a kilogram is not a measure of weight, it is a measure of mass),G is the universal gravitational constant, M is the mass of the Earth, m is 1 for your 1 kg mass and R is the radius of the Earth, in meters. Solve for M.

2007-05-25 01:45:14 · answer #2 · answered by campbelp2002 7 · 1 0

yes! using Newton's Law of Universal Gravitation.

F is the gravitational force between two masses (in Newtons)

m and M are the two masses (in kilograms)

R is the distance between the center of the two masses (in metres)

F = G x m x M / R2



The force between the Earth and the sphere can be measured by dropping the 1 kg sphere to Earth.

F = m x a

F = 1 kg x 9.8 m/s2

F = 9.8 kg x m/s2



We already know that:

R = 6.4 x 106 m

G = 6.7 x 10-11 Nm2/kg2



Therefore:

F = G x m x M / R2

Step 1: 9.8 kg x m/s2 = 6.7 x 10-11 Nm2/kg2 x 1 x M / (6.4 x 106 m)2

Step 2: M = 9.8 kg x m/s2 x (6.4 x 106 m)2 / 6.7 x 10-11 Nm2/kg2 x 1

Step 3: M = 9.8 x (6.4 x 106)2 / 6.7 x 10-11

Step 4: M = 9.8 x (4.096 x 1013) / 6.7 x 10-11

Step 5: M = 4.01408 x 1014 / 6.7 x 10-11

Answer: M = 6.0 x 1024 kg

Therefore the mass of the Earth is 6.0 x 1024 kg or 6.0 x 1021 tonnes.

2007-05-25 00:51:43 · answer #3 · answered by Avondrow 7 · 3 2

Hello
I typed that in on a net search and this site came up:
http://rds.yahoo.com/ I this is not working just type in earths weight and the answer I saw was about the second choice.

Hope this helps :)

P.S. I like your avatar picture

2007-05-25 01:00:57 · answer #4 · answered by Anonymous · 1 0

I've often wondered if it is at all possible to work this out because its simple enough to work out the complete area but what is not known are the make up near the core whether light or heavy substance is present and how much against each other . I personally think its impossible to arrive at an actual figure//Avondrow your figures are bunkum your evading the question with a load of flannel

2007-05-25 00:59:19 · answer #5 · answered by srracvuee 7 · 2 3

Avondrow's answer is neither bunkum nor flannel - it is exactly correct, as anyone with any knowledge of Physics would know. So why the "thumbs down"?

(Most of us are assuming that when Knowall says "weight" he means "mass" - of course its weight is zero...)

2007-05-25 05:56:51 · answer #6 · answered by Martin 5 · 1 0

The Earth is in free-fall, orbiting the sun. Therefore its weight is exactly zero.

2007-05-25 12:23:10 · answer #7 · answered by Anonymous · 0 0

Six-sextillion 592 quintillion tons.

2007-05-25 02:01:53 · answer #8 · answered by Billy Butthead 7 · 2 0

Try looking here;

http://en.wikipedia.org/wiki/Earth

Look under; Physical characteristics, Mass

2007-05-25 01:10:21 · answer #9 · answered by notrightinthehead 3 · 1 0

5.976 * 10 to the power 24 kilogrammes

2007-05-25 01:06:06 · answer #10 · answered by Anonymous · 1 0

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