Help in math, please??

Question

Solve by using the most appropriate method. Give irrational answers in simplest radical form.

8x^2 + 11x = 0

Solve by using the most appropriate method. Give irrational answers in simplest radical form.

4x^2 - 2x -3 = 0

These are the last two problems and I really don't understand them. I think they're going to be on my test. :( Please help.

Thank you.

Answer 1

8x^2 + 11x = 0
Factoring
x(8x+11)=0
x=0
8x+11=0
8x=-11
x=-11/8
Solution set --- (-11/8, 0)


4x^2-2x-3=0
Use the quadratic formula
x=[2±sqrt(4+4*4*3)]/8
=[2±sqrt(52)]/8
=2[1±sqrt(13)]/8
=[1±sqrt(13)]/4

Solution Set --- ([1+sqrt(13)]/4, [1-sqrt(13)]/4)

Answer 2

Question 1
x = [ - 11 ± √121 ] / 16
x = 0, x = - 22 / 16
x = 0 , x = - 11 / 8
Question 2
x = [ 2 ± √52 ] / 8
x = [2 ± 2√13] / 8
x = [1 ± √13] / 4 is acceptable form for answer.

Answer 3

Just use the quadratic formula to solve them. If you don't have the quadratic memorized, you need to.

There are other ways to factor polynomials but the quadratic will solve all polynomials, and after a few tries is very easy. Just remember the number before the x^ is A the number before x is B and the remaining real number is C.

Answer 4

use quadratic equation,
1. 0 & -11/8
2. 1.1514 & -0.6514

Answer 5

1)-11/8,0
2)1+/-sqrt(13) / 4