what is x, and how.
2007-05-24 20:22:19 · 6 answers · asked by jredsje 2 in Science & Mathematics ➔ Mathematics
x/x+6 = 3/x
x(x+6)x/x+6 = 3/x(x)(x+6)
x² = 3x+18
x² -3x-18= 0
(x-6)(x+3) = 0
x=6,-3
:) good luck to you
2007-05-24 20:26:21 · answer #1 · answered by Nick 2 · 0⤊ 0⤋
If you mean x / (x+6) = 3/x and not (x/x) + 6 = 3/x, then multiply both sides by (x+6) and then by x. This gets rid of the fractions.
(x+6) * x/(x+6) = (3/x) * (x+6)
x = (3/x) * (x+6)
x*x = (3/x) * (x+6)*x
x^2 = 3(x + 6)
Now simplify and solve as a quadratic
x^2 = 3x + 18
x^2 - 3x - 18 = 0
(x - 6)(x + 3) = 0
So x = 6, -3
2007-05-25 03:38:03 · answer #2 · answered by Anonymous · 0⤊ 1⤋
x/(x+6) = 3/x multiply each side by x(x+6)
x^2 = 3(x+6)
x^2 - 3x - 18 =0
(x-6)(x+3)=0
x=6 or x=-3
2007-05-25 03:32:10 · answer #3 · answered by Jen 3 · 1⤊ 0⤋
x / (x + 6) = 3 / x
x² = 3.(x + 6)
x² = 3x + 18
x² - 3x - 18 = 0
(x - 6).(x + 3) = 0
x = 6 , x = - 3
2007-05-25 03:29:50 · answer #4 · answered by Como 7 · 0⤊ 0⤋
x^2 = 3(x+6) (cross mutilply)
x^2 -3x - 18 = 0
(x-6) (x+3) = 0
so x= 6 or -3
2007-05-25 03:41:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x/(x+6)=3/x
x/(x+6)-3/x=0
[(x^2)-3(x+6)]/x(x+6)=0
x^2-3x-18=0
(x-6)(x+3)=0
x=6 or -3
2007-05-25 03:42:34 · answer #6 · answered by jackleynpoll 3 · 0⤊ 0⤋