1) x > -10
2) x < 10
3) x > 10
4) x > -10
5) x < -0.10
2007-05-24 16:23:33 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
0.9x + 3 > 0.6x
0.9x - 0.6x > -3
0.3 x > -3
x > -3/0.3
x> -10
Answer: 1 and 4
2007-05-24 16:31:45 · answer #1 · answered by Janet 2 · 0⤊ 0⤋
1 and 4 x>-10
2007-05-24 23:26:46 · answer #2 · answered by Edward F 1 · 0⤊ 0⤋
Solving an inequality is much like solving an equation, with the exception that:
Multiplying or dividing both sides of the inequality by a negative number reverses the sense of the inequality. That is, a < (less than) relationship becomes a > (greater than) and vice versa. Similarly, the <= (less than or equal to) will transform into the >= (greater than or equal to) relational operator and vice versa.
Reversing the sides of the inequality also reverses the sense of the inequality.
Subtracting 0.6x from both sides gives
0.3x + 3 > 0
Adding 3 to both sides gives
0.3x > -3
Dividing both sides by 0.3 finally gives
x > -10
The sense of the inequality remains the same because we are dividing by a positive rather than a negative number.
2007-05-24 23:36:24 · answer #3 · answered by devilsadvocate1728 6 · 0⤊ 0⤋
first subtract .6x from both sides
0.9x + 3 > 0.6x
0.3x +3 > 0 subtract 3 from both sides
0.3x > -3 divide both sides by 0.3
x > -10
2007-05-24 23:38:03 · answer #4 · answered by Trini 3 · 0⤊ 0⤋
0.9x+3>0.6x
0.9x-0.6x>-3
0.3x>-3
x>-3/0.3
x>-10
2007-05-25 01:17:35 · answer #5 · answered by sam 3 · 0⤊ 0⤋
9x + 30 > 6x
3x > - 30
x > - 10
ANSWER 1)
2007-05-25 05:58:20 · answer #6 · answered by Como 7 · 0⤊ 0⤋