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I have to solve for X and Y and then graph it. The problem is 6y+1=13 I cannot figure out where to put X to begin to solve this, Please help.

2007-05-24 16:04:12 · 12 answers · asked by DvLn1220 2 in Science & Mathematics Mathematics

12 answers

thats because the 1 is actually 1x
so the equation is 6y+1x=13

hope it helps

2007-05-24 18:23:04 · answer #1 · answered by daringsham 2 · 0 0

In this case, the relationship does not depend on x, so the same value(s) of y will work no matter what you choose for your value of x. This happens when you are asked to graph one or more horizontal lines. Such a line will have a slope of zero. When the equation is written in slope-intercept form (y = mx + b) the coefficient in front of the x will likewise be zero, causing the term involving x to drop out of the equation altogether. Similarly, if the graph is a vertical line, the variable y won't appear in the equation.

This example, by the way, reduces to y = 2, which is graphed as a horizontal line 2 units above the x axis.

2007-05-24 23:18:06 · answer #2 · answered by devilsadvocate1728 6 · 0 0

Think of it in terms of the graph. Solve the problem in these steps.

1) Separate the y term from the other numbers.
6y=12

2) Solve for y.
y=2

If you graph the line y=2, you will get a horizontal line at y=2, and therefore the line will never cross the x-axis. So, x=0.

2007-05-24 23:12:59 · answer #3 · answered by drmd119 2 · 0 0

If there isn't an x, the graph will be a straight horizontal line 2 units above the x-axis... y always equals 2 regardless of what x is.

2007-05-24 23:10:24 · answer #4 · answered by Anonymous · 0 0

6y + 1 = 13
6y = 12
y = 2

Plot several points with ANY x coordinate and y coordinate = 2. Draw a line through them. You get a horizontal line that crosses the y axis at 2. Any time there's y and no x, you've got a horizontal line. If there's x and no y, you get a vertical line.

2007-05-24 23:11:47 · answer #5 · answered by Philo 7 · 1 0

Without any "x" in the equation, you're obviously not solving for it. You're solving for Y, which is clearly, 2.

To graph that, simply draw a line through 2 on the y-axis. X doesn't matter - it runs from minus infinity to plus infinity.

2007-05-24 23:10:55 · answer #6 · answered by HeadScratcher98 3 · 0 0

I would have to guess that there is no value for x. So instead of having a point on a graph, (x,y) you would have a line where x can be any number and y = 2

2007-05-24 23:09:35 · answer #7 · answered by Jen 3 · 0 0

y = mx + b is the equation used for graphing lines.
m = slope
b = y-intecept

Transform your equation to resemble the standard form

6y = 12
y = 2
Interpreted, y = 0x + 2
Therefore, m = slope = 0
b = y-intercept = 2
this equation yields a horizontal line

2007-05-24 23:23:05 · answer #8 · answered by Brian N 2 · 0 0

You then just have a line on the y axis. and x = 0

2007-05-24 23:08:59 · answer #9 · answered by badoil_49 2 · 0 0

could you be looking for the x-intercept. just solve to get y on one side then graph and see where it crosses x axis.

2007-05-24 23:13:03 · answer #10 · answered by snowboarder899 1 · 0 0

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