FACTOR
(2x - 1) ( x - 3) = 0 ====> zero property rule
either
2x-1 = 0 OR x-3=0
x = 1/2 OR x = 3
=]
2007-05-24 15:48:46
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answer #1
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answered by Anonymous
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The two answers will be the "roots" of the equation, or, where the function crosses the x-axis. A function will have, at most, as many roots as the power function, in this case 2 (x squared). A function can have no roots if it lies completely above y=0.
To find the roots you need the quadratic formula, the link to which can be found below (wikipedia), as it's too complex to express using inline syntax.
You will find that if you use the quadratic formula you should get 2 roots, of 3 and 0.5. (x-values)
Note that there are other methods, both exact ones and approximation ones. The other exact method is to factorise the equation, in this case
(2x - 1)(x-3).
Then take each bracket separately and give x a vale which makes the brackets equal zero. In this case, x=0.5 makes the left bracket zero and x=3 makes the right bracket zero. Viola!
2007-05-24 15:57:40
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answer #2
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answered by tlb AU 2
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well in my class we multiply the leading coeficiant by the c term.
that would make the new eqatuion
x^2-7x+6
then find then factors of 6 that make -7 (don't forget the negative possiblities
so the factors that work are -6 and -1
then the equation changes to
(x-6)(x-1)=0
divide both factors by 2 (because that is what you mulitplied by at the beg.)
now (x-3) (2x-1)=0
set both factors equal to 0
x-3=0 x=3
2x-1=0 x=1/2
2007-05-24 15:54:26
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answer #3
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answered by Mina G 1
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(2x - 1)(x - 3) = 0
2x - 1 = 0
2x = 1
x = .5 (a.k.a 1/2)
x - 3 = 0
x = 3
x = (1/2), 3
if you plug 3 in
2(3)^2 - 7(3) + 3 =0
2(9) - 21 + 3 = 0
18 - 21 + 3 = 0
21 - 21 = 0
0 = 0 <-- it's a true statement, it will also work for .5
2007-05-24 15:51:58
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answer #4
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answered by Anonymous
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2x^2-7x+3=0
(2x-1)(x-3)=0
x= 1/2 or x=3 =0
2007-05-24 15:50:00
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answer #5
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answered by risa songn 2
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2x^2 - 6x - x +3 =0 (splitting 7x as 6x and x)
=2x(x-3) - 1(x-3)=0
(x-3)(2x-1) = 0
either (x-3) =0 or (2x-1) =0
either x = 3 or x = 1/2
2007-05-24 15:52:34
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answer #6
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answered by mR.qUESTiON?? 2
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2x² - 7x + 3=0
Factor
(2x - 1)(x - 3) = 0
x = 1/2, x = 3.
.
2007-05-24 15:52:07
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answer #7
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answered by Robert L 7
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well now that u have realized that it is quadratic.
best way to do it .. is to use the formula.. saves a lot of time
(7) + - sqrt (49 - 24)/4
7 +- 5 / 4
so x =
7 + 5 / 4
and 7 - 5 / 4
therefore
x = 3
x = 1/2
2007-05-24 15:51:18
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answer #8
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answered by sudhi_kandi 3
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2X^2-7X+3=0
Factor it... this is basically guess and test.
you get (2X-1)(X-3)
Set them both equal to zero:
2X-1=0 X-3=0
2X=1 X=3
X= .5
So, X = 3 and .5
2007-05-24 15:50:49
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answer #9
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answered by Anonymous
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(2x - 1).(x - 3) = 0
x = 1/2 , x = 3
2007-05-24 20:22:40
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answer #10
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answered by Como 7
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