use the quadratic formula to solve 5x-4x^2=1?

Answer 1

The equation must be in standard form before we can apply quadratic formula
a x^2 + bx + c = 0
-4x^2 + 5x - 1 = 0

a = -4
b = 5
c = -1

x = [ - b +/- sqrt(b^2 - 4ac) ] / (2a)

- 5 +/- sqrt (25 - 4(-1)(-4) )
______________________
2*-4

-5 +/- sqrt(9)
__________
-8

-5 +/- 3
_______
8

-5 + 3 = -2
________ = -2/8 = -1/4
8

-5 - 3 = -8
________ = -8/8 = -1
8


ANSWERS ARE x= - 1 and x= - 1/4

=]

check by putting into original equation! YEP - correct!

.

Answer 2

Quadratic Formula- x= -b + or - the sqaure root of b^2-4ac all over 2a

5x-4x^2=1
5x-4x^2-1=0
-4x^2+5x-1=0

x=-5+3 over 2*-4
x=-2 over -8
simplifies to
x=1/4

x=-5-3 over 2*-4
x=-8 over -8
simplifies to
x=1

Your Answer Is:
x=1/4
x=1

100% sure

Answer 3

4x² - 5x + 1 = 0
x = [ 5 ± √(25 - 16) ] / 8
x = [5 ± √9 ] /8
x = 8/8 , x = 2 / 8
x = 1, x = 1/4
Or by factorising:-
(4x - 1).(x - 1) = 0
x = 1 , x = 1/4

Answer 4

won't be able to remember, someplace around 2 hundred pshh, whoever became the single that have been given extra desirable than 7000 factors each and every week the two has a severe undertaking or shares his/ her account with many people and take turns answering 24/7!

Answer 5

X1= -5+sqrt(25-16)/-8=-5+3= - 2/-8= 0.25
x2= -5 -3/-8 = -8/-8=1

Answer 6

quadratic formula

-b+_sqroot(b^2-4ac) all over 2a

should give u 2 asnwers cuz of X^2