Chemistry Help..?

Question

Butane gas burns in air releasing 3000kJ.

1. Write balanced chemical equation + physical state.

2. What type of reaction?

3. If 116g of butane are completely burned, what is the total mass of the products produced? + How much heat (in kJ) are produced?

4. If butane is not completely burned, name and write the new compound produced.


THANKS!

Answer 1

1. 2 C4H10(g) + 13 O2 (g) ---> 8 CO2 (g) + 10 H2O (l)
2. Combustion
3. MW C4H10 is 58 g/mole, so 116 g is 2 moles. You will get 8 moles of CO2 (at 44 g/mole, 352 g) and 10 moles of water (at 18 g/mole, 180 g) for a total mass of 532 g. The 3000 kJ is per mole of butane, so you will produce 6000 kJ.
4. Incomplete combustion yields either carbon as soot or carbon monoxide, CO.

Answer 2

i would love to say "do your own homework!" but, just in case you retort "but i dont know how!", here's a few tips.

1) butane, C4H10 (or any hydrocarbon, for that matter), in the presence of sufficient oxygen, ALWAYS produces CO2 and H2O. so... balance the equation yourself :D

2) convert the mass of butane to the number of moles (by dividing Mr); and according to the mole ratio of your reactants and products, find accordingly the mass of your products (by multiplying with their Mr)

4) if insufficient oxygen is present, it will either produce carbon monoxide, CO, or soot, C. and H2O. always.

thats about as much information as you'll need :) any more and i might as well go to school for you. cheers :)