HTcO4 + NaOH --------> NaTcO4 + H2O (l)
if u begin with 4.5 mg of Tc metal, how much NaTcO4 can be madE? what mass of NaOH ( in grams ) is required to convertt all of the HTcO4 into NaTCO4???
2007-05-24 15:05:16 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Atomic weights: Tc=98 Na=23 O=16 NaTcO4=185
4.5mgTc x 1mmolTc/98mgTc x 1mmolNaTcO4/1mmolTc x 185mgNaTcO4/1mmolNaTcO4 = (4.5)(1.85)/(98) = 0.85 mg NaTcO4
2007-05-24 15:17:39 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
All the compounds in this equation have a coefficient of one, meaning one mol of HTcO4 combined with one mol of sodium hydroxide will yield one mol of the salt and one mol of water. So figure out how many moles 4.5 mg of the acid is and thats the amount of NaOH you'll need (since NaOH is a strong base) and the amount of salt that will be formed.
Cheers.
2007-05-24 15:25:25 · answer #2 · answered by aridotion 1 · 0⤊ 0⤋