Let the first number = x
Then the 2nd = 4x
the third = 5(4x) = 20x
Then
x + 4x + 20x = 500
25x = 500
x = 20 first number
4x = 80 second number
20x = 400 third number
,.
2007-05-24 14:43:01
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answer #1
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answered by Robert L 7
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500=x+4x+20; 5 times the second
x=20
20, 80, 400
2007-05-24 14:50:56
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answer #2
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answered by mariaFB 3
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x + 4x + 5(4x) would be more correct.
x + 4x + 20x = 500
25x = 500
x = 20
20 + 4(20) + 5(4 x 20) = 500
20 + 80 + 400 = 500
2007-05-24 14:41:11
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answer #3
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answered by Matthew H 2
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easy..!!!
number 1 x 20 x+4x+20x = 500
number 2 4x 80 25x = 500
number 3 5(4x) 400 x = 20
total 500
2007-05-24 14:46:01
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answer #4
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answered by sandra v 1
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If 4x is the second then thats 5 times 4x so thats 20x so its really x+4x+20x=500 or 25x=500 so x=20
2007-05-24 14:40:08
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answer #5
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answered by Tyler M. 2
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Your problem is that you are setting up the 3rd # as 5 times the first instead of 5 times the 2nd. so you're terms should be written as
x=1st # 4x=2nd # 5(4x)=3rd # . Your equation would be written as :
x+4x+20x=500
25x=500
x=20; 4x=80, 20x=400
2007-05-24 14:41:24
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answer #6
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answered by txmama423 3
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you're assuming the 3 numbers are all the same, but they're not....
x+y+z=500
you know:
y=4*x (second number is 4 times the first)
z=5y (third number is 5 times the second)
now plug and chug
x + y + z = 500
x + 4x + 5y = 500
5x + 5(4x) = 500
5x + 20x = 500
25x=500
x=20
y=4x=80
z=5y=400
2007-05-24 14:44:10
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answer #7
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answered by Jen 3
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ah dere is the mistake the third no. is five times the second
the 2nd no is 4x
so the 3rd no is 5*4x
if its jus 5x it will be five times the 1st no
so the eq is x+4x+20x=500
25x=500
x=500/25 =20
i think u cld find the oder two values by substitutitng the value of x
2007-05-24 14:39:36
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answer #8
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answered by Anonymous
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your third number is five time the second. so, 5(4x). it's supposed to be 20x.
x+4x+20x=500
25x=500
x=20
2007-05-24 14:40:06
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answer #9
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answered by Yssa A 3
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x + 4x + (4x)5 = 500
2007-05-24 14:40:23
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answer #10
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answered by Mark 6
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