Determine the slope and y-intercept of the graph of 12 + 3y = -2x.
How do i do that?
2007-05-24 14:30:26 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Make it into the "y = mx + b" form, first.
12 + 3y = -2x
3y = -2x - 12
y = -(2/3)x - 4
So the slope is -2/3.
To find the y-intercept, set x to 0.
12 + 3y = 0
3y = -12
y = -4
The y-intercept is -4.
2007-05-24 14:37:14 · answer #1 · answered by atomicjohnson 3 · 0⤊ 0⤋
Try to get this equation to look like the slope-intercept equation of a line: y = mx + b, where m=slope and b=y-intercept.
12 + 3y = -2x
3y = -2x -12
y = (-2/3)x - 4
so, m (slope) = (-2/3)
b (y-intercept) = -4
2007-05-24 21:37:44 · answer #2 · answered by sneysi 2 · 0⤊ 0⤋
12 + 3y = -2x
The slope intercept equation is in the form
y = mx + b
Your equation, let's solve for y
3y = -2x - 12
y = -(2/3)x - 4
The slope is
m = -(2/3)
The y intercept is
b = -4
.
2007-05-24 21:38:19 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋
isolate 'y' on one side of the equation by subtracting 12 from both sides and dividing both sides by 3. Then the number that doesn't have 'x' is your y-intercept.
Another way to find the intercept is to substitute zero for 'x' and solve for 'y.'
2007-05-24 21:34:39 · answer #4 · answered by MoonSorceress 4 · 0⤊ 0⤋