x^2+3x-40=0
2007-05-24 14:29:06 · 12 answers · asked by Cooter 1 in Science & Mathematics ➔ Mathematics
X^2 + 3X - 40 = 0
(X+8) (X-5) = 0
Roots are -8 and 5
You need to factor the left side of the equation, then read it from left to right like this: X^2 +8 X - 5X = 0
The (+8 X - 5 X) gets you the 3 X
2007-05-24 14:33:37 · answer #1 · answered by Anne M 5 · 0⤊ 0⤋
2 roots both real.
x2 + 3x - 40 = 0
(x+8)(x-5) = 0
x = -8
x = 5
2007-05-24 14:32:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x² + 3x - 40 = 0
(x + 8)(x - 5) = 0
x = 5, x = -8
Roots are real and rational
.
2007-05-24 14:32:55 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋
This is a quadratic, so 2 roots. if x = 0 then x^2 + 9x=0 if x = -9 then x^2 + 9x=0
2016-05-17 07:32:31 · answer #4 · answered by samira 3 · 0⤊ 0⤋
Factor
(x + 8)(x - 5) = 0
x = -8, 5
2 real roots!
2007-05-24 14:31:19 · answer #5 · answered by richardwptljc 6 · 0⤊ 0⤋
the answers are 5 and -8. there are two roots
2007-05-24 14:37:23 · answer #6 · answered by Pitbull 1 · 0⤊ 0⤋
x^2+3x-40=0
(x____)(x____) = 0
(x + 8)(x - 5) = 0
x = -8 or +5
2 integer, real roots
2007-05-24 14:32:41 · answer #7 · answered by Anonymous · 0⤊ 0⤋
It's going to have two roots.
x = (-3 +/- sqrt(9 + 160))/2
x = (-3 +/- sqrt(169))/2
x = (-3 +/- 13)/2
x = -16/2 or 10/2
x = -8 or 5
These roots are both real and rational.
2007-05-24 14:32:01 · answer #8 · answered by TychaBrahe 7 · 0⤊ 0⤋
(x-5)(x+8)... and I am not really sure by what you mean, type of roots
2007-05-24 14:31:38 · answer #9 · answered by army_soldiersgirl 2 · 0⤊ 0⤋
(x+8)(x-5)
2007-05-24 14:31:53 · answer #10 · answered by Anonymous · 0⤊ 0⤋