whats x?
2007-05-24 13:54:35 · 6 answers · asked by Adam T 1 in Science & Mathematics ➔ Mathematics
(x-4)(x-8)8=800
(x-4)(x-8)=100
x^2-12x+32=100
x^2-12x-68=0
use quadratic formula to solve for x..
2007-05-24 13:59:52 · answer #1 · answered by Yssa A 3 · 0⤊ 0⤋
(2x-8)(x-8)4=800 divide both sides by 4
(2x-8)(x-8)=200 use FOIL
2x^2-24x+64=200 subtract 200 from each side
2x^2-24x-136=0 divide by 2
x^2-12x-68=0
x=(12屉144+4*68))/2
x=(12屉416)/2
x=(12±4â26)/2
x=6±2â26
x=6+2â26
x=6-2â26
2007-05-24 21:04:46 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
First simplify.
(2x-8)(x-4)4=800
(2x^2-16x+32)4=800
6x^2-64x=672
Now use the quadratic formula.
x=[-b +/- sqrt (b^2-4ac)]/2a
x=8 or x=0
2007-05-24 21:03:03 · answer #3 · answered by de4th 4 · 0⤊ 1⤋
4*(2x^2 -24x + 64) - 800 = 0
8x^2 - 96x - 544 = 0
x^2 - 12x - 68 = 0
x = (12 +/- sqrt(144 + 272))/2
x = (12 +/- sqrt(416))/2
x = 6 +/- 2 * sqrt(26)
2007-05-24 21:03:35 · answer #4 · answered by TychaBrahe 7 · 0⤊ 0⤋
(2x-8)(x-8)=200
6+ or - 2*sqrt of 26
2007-05-24 21:01:37 · answer #5 · answered by Murtagh 3 · 0⤊ 0⤋
Sorry, but you really should do your own homework. I will give you a hint.....the answer(s) could involve imaginary roots.
2007-05-24 21:14:20 · answer #6 · answered by Anonymous · 0⤊ 0⤋