x+y=3
5x-2y=11
2007-05-24 13:47:25 · 7 answers · asked by Agnew 1 in Science & Mathematics ➔ Mathematics
2x+2y=6
5x-2y=11
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7x=17
x=17/7, now substitute this into either equation to solve for y.
2007-05-24 13:52:43 · answer #1 · answered by leo 6 · 0⤊ 0⤋
You can rather
a) Graph both lines, and see where they intersect
or
b) Use substitution.
x + y = 3
5x-2y=11
x = 3-y
5 (3-y) - 2y =11
15-5y-2y=11
-7y= -4
y = 4/7
4/7+x=3
x = 3-4/7
x= 17/7
Therefore, you would say that the point of intersection is (17/7, 4/7)
2007-05-24 20:53:59 · answer #2 · answered by de4th 4 · 0⤊ 0⤋
x+y=3
5x-2y=11
The next step is to substitute for one of the variables
x=3-y
5(3-y)-2y=11
15-5y-2y=11
15-7y=11
-7y= -4
y= 4/7
Then you Subtitute answer to any of the problems
x+(4/7)=3
x= 17/7
2007-05-24 21:03:29 · answer #3 · answered by / 2 · 0⤊ 0⤋
Solve the first equation for y to get
y = 3 - x
Substitute this into the second equation
5x - 2(3 - x) = 11
5x - 6 + 2x = 11
7x - 6 = 11
7x = 17
x = 17/7
Now substitute into first equation to find y
17/7 + y = 3
y = 3 - 17/7
y = 4/7
Solution is (17/7,4/7)
2007-05-24 20:54:16 · answer #4 · answered by piggy30 3 · 0⤊ 0⤋
x+y=3
5x-2y=11
x=3-y
5(3-y)-2y= 11
15-5y-2y= 11
15-7y= 11
-7y= -4
y= 4/7
x+(4/7)=3
x= 17/7
2007-05-24 20:52:07 · answer #5 · answered by chess2226 3 · 0⤊ 0⤋
sub X= Y-3
5(y-3)-2y=11
3y-15-2y=11
3y-15=11
3y= -4
y=-4/3
y= -11/3
2007-05-24 21:04:30 · answer #6 · answered by bcnd 3 · 0⤊ 0⤋
x+y=3-----(1)
5x-2y=11-----(2)
(1)*2 = 2x+2y=6----(3)
(2)+(3)= 7x=17, x=17/7
(1)==>17/7+y=3
y=4/7
Ans: x=17/7, y=4/7
2007-05-24 21:00:15 · answer #7 · answered by R&B Thug 7 · 0⤊ 0⤋