area = pi* (radius)^2
2007-05-24 13:21:47
·
answer #1
·
answered by Yssa A 3
·
1⤊
0⤋
The circle is the infinite limit polygon. If we consider a equilateral polygon of n sides with a radius r from its center to any of the n vertices, its area is (nr^2)sin(2pi/n)/2.
So the area of a circle is [(r^2)/2]lim(n->infinity) nsin(2pi/n).
Since sin(2pi/n) --> 2pi/n as n--> infinity, the area goes to
[(r^2)/2](n)(2pi/n) = pi(r^2), the familiar equation.
2007-05-24 20:32:08
·
answer #2
·
answered by jcsuperstar714 4
·
0⤊
0⤋
A=Ï*r^2 where A is the area, r is the radius (1/2 the diameter) & Ï is a universal constant &
Ï=3.1415926535897932384626433832795.....
2007-05-24 20:58:24
·
answer #3
·
answered by yupchagee 7
·
0⤊
0⤋
A = (pi) r^2
So multiply the radius times itself and then write the pi symbol next to the product to leave it "in terms of pi" or you can multiply the product times 3.14 for an approximate answer.
2007-05-24 20:22:55
·
answer #4
·
answered by T F 4
·
0⤊
0⤋
To find the area of a circle, memorize this equation:
3.14r^2
Take the radius and square it, then multiply by 3.14, or pi.
2007-05-24 20:22:16
·
answer #5
·
answered by Anonymous
·
0⤊
1⤋
pi times r^2, where r is the radius
2007-05-24 20:22:20
·
answer #6
·
answered by EppsFan314 1
·
0⤊
0⤋
Square the radius and multiply by pi.
A = Ï r²
.
2007-05-24 20:24:12
·
answer #7
·
answered by Robert L 7
·
0⤊
0⤋
area of a circle is pi*radius^2
pi is 3.14159265358979323........
(Are you serious?)
2007-05-24 20:22:47
·
answer #8
·
answered by chess2226 3
·
1⤊
0⤋
Ïr^2 <= is the formula
2007-05-24 20:27:11
·
answer #9
·
answered by amethyst_fire_lily 2
·
0⤊
0⤋
A = Ï r²
2007-05-24 20:27:01
·
answer #10
·
answered by anonymous 2
·
0⤊
0⤋