Two legs of a right traingle are 2 and the square root of 5. Let angle A be the smallest angle of triangle ABC. what is cos A?
2007-05-24 12:41:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The length of the hypotenuse is sqrt(2^2 + 5) = sqrt(9) = 3.
The smallest angle is the one opposite the shortest side, which is the one of length 2.
cos(A) = sqrt(5) / 3.
2007-05-24 12:47:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋
ok since the two legs are 2 and sqrt(5) the smallest leg is going to be across from the smallest side which is 2. The hypotenuse is 3. Since cos is adjacent over hypotenuse you will do arc cosine(sqrt(5)/3)= 0.730
2007-05-24 19:50:40 · answer #2 · answered by chinniballer 1 · 0⤊ 0⤋
hypotenuse is â[ 2² + (â5)²] = â9 = 3, and 2 < â5 â 2.24, so
cos A = (â5)/3
2007-05-24 19:48:05 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
cos A would have to be 2/sqrt(5)
which is 0.894(3.d.p)
...I think
2007-05-24 19:45:49 · answer #4 · answered by Anonymous · 0⤊ 0⤋