The sum of a deck of cards?

Question

does anyone know the sum of a deck of cards if aces are low jacks are 11 queen 12 king 13

1x1x1x1x2x2x2x2x3x3x3x3x4x4x4x4x5x5x5x5x6x6x6x6x7x7x7x7x8x8x8x8x9x9x9x9x10x10x10x10x11x11x11x11x12x12x12x12x13x13x13x13

I know it's product but sum sounds better and im tired

Answer 1

4(1+2+3+4+5+6+7+8+9+10+11+12+13)
4 x 91 = 364

Answer 2

"Sum" means add not multiply, so 1+ 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 = 91
then 4 suites
91*4 = 364

Answer 3

You are adding up the numbers one through thirteen four times.

When adding a series of numbers, take the average and multiply by the how many numbers are in the series. In the series starting with one and ending with thirteen there are thirteen numbers. The average is seven. So, 7 x 13 = 91 There are four series, so 91 x 4 = 364. The sum of the deck of cards is 364.

Answer 4

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Answer 5

If you want the sum of all the cards, you need to use the sum of numbers formula, which is:

n(n+1) / 2...

In your case, each suit would be:

13(14) / 2....this result is:

91...

since you have 4 suits, the answer is

4(91)= 364

Answer 6

Ignoring the jokers, the answer is simple. In any suit, pair ace with king, deuce with queen, et cetera. There are six pairs, with the seven left over, and each pair adds to 14. So the pips in any suit add to 14 x 6 + 7 = 91. With four suits, you have 364.

Answer 7

1 -> 13 = 6(14) = 84 + 7 = 91

91(4 suits) = 364

Answer 8

4*13*14/2 = 364

Answer 9

364

Answer 10

do you want sum or product? sum would be

1+1+...+13+13 =
4(1+2+...+12+13) =
4(13/2)(14) =
364

product is (13!)^4 ≈ 1.5 x 10^39