I belive that the sqrt of x^2 is = to the absolute value of x..
since x could be positve or negative..
here, x can only be a postive, value since the root of any value cannot be negative, if x is a negative value, it would not be true..
2007-05-24 12:09:05
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answer #1
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answered by JAC 3
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Not true for all values of x. Like others said,
√x²=|x|
Not just x.
x can be both positive or negative. Negative numbers squared are positive. Only positive numbers can be square rooted (not sure that's a word) or else they become imaginary. And the square root of any positive number can also be negative. Like -1 times -1, equals 1.
2007-05-24 16:25:26
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answer #2
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answered by Anonymous
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True. As x is squared (^2) it will always be a positive number, or 0.
But the right answer is: Sq Rt x^2 = +x & -x
2007-05-24 12:10:42
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answer #3
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answered by Anonymous
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No. Consider x = -2, for which it is false. Square roots are always taken to be positive.
2007-05-24 12:30:20
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answer #4
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answered by Anonymous
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It is false because if x=-4 ( any negative ) x^2=16
and sqrt(x^2)=4
In general sqrt(x^2) = I x I
2007-05-24 12:09:54
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answer #5
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answered by santmann2002 7
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√(x²)=|x|.
(√x)²=x or is undefined over the reals.
2007-05-24 12:17:15
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answer #6
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answered by YCZ6 2
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