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2007-05-24 12:04:18 · 6 answers · asked by daisytroop870 1 in Science & Mathematics Mathematics

6 answers

I belive that the sqrt of x^2 is = to the absolute value of x..

since x could be positve or negative..

here, x can only be a postive, value since the root of any value cannot be negative, if x is a negative value, it would not be true..

2007-05-24 12:09:05 · answer #1 · answered by JAC 3 · 0 0

Not true for all values of x. Like others said,
√x²=|x|
Not just x.
x can be both positive or negative. Negative numbers squared are positive. Only positive numbers can be square rooted (not sure that's a word) or else they become imaginary. And the square root of any positive number can also be negative. Like -1 times -1, equals 1.

2007-05-24 16:25:26 · answer #2 · answered by Anonymous · 0 0

True. As x is squared (^2) it will always be a positive number, or 0.
But the right answer is: Sq Rt x^2 = +x & -x

2007-05-24 12:10:42 · answer #3 · answered by Anonymous · 0 1

No. Consider x = -2, for which it is false. Square roots are always taken to be positive.

2007-05-24 12:30:20 · answer #4 · answered by Anonymous · 0 1

It is false because if x=-4 ( any negative ) x^2=16
and sqrt(x^2)=4
In general sqrt(x^2) = I x I

2007-05-24 12:09:54 · answer #5 · answered by santmann2002 7 · 0 0

√(x²)=|x|.
(√x)²=x or is undefined over the reals.

2007-05-24 12:17:15 · answer #6 · answered by YCZ6 2 · 1 0

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