Help with Equations PLEASE!?

Question

You have to solve for the variables:
2(1+c)-(2+c)=10
2/3M=M+4
4(5-2b)+3c(2b-1=7(b+2)

Answer 1

2(1+c)-(2+c)=10
2+2c-2-c=10
2-2 +2c-c=10
c= 10

2/3M= M+4
to get rid of the fraction multiply everything on both sides by three.
3(2/3m)= 3(m+4)
2m= 3m+12
-3m+2m=12
-m=12
m= -12

4(5-2b)+3c(2b-1)=7(b+2)
20-8b+6cb-3c= 7b+ 14
-8b-7b+6cb -3c= -20+14
-15b+6cb-3c= -6
-3(5b-3cb+c)=-6
i don't think the question to the last one is correct check the question again then post it

Answer 2

1.
2(1 + c) - (2 + c) = 10 first get rid of ( ) by distributing
2 + 2c - 2 - c = 10 now regroup and put the like terms together
(2 - 2) + (2c - c) = 10 and we get
0 + c = 10
c = 10 final ans.

2.
2/3M = M + 4 subtract M from both sides we get...
-1/3M = 4 now multiply both sides by 3 and we get
-1M = 12 now divide both sides by -1
M = -12

3.
4(5-2b)+3c(2b-1)=7(b+2) First step get rid of ( ) by distributing...
20 - 8b + 6bc - 3 = 7b + 14 (this one you can not solve because it has to variables but you can simplify or solve one variable in terms of the other.
17 - 8b + 6bc = 7b + 14 subtract 14 from both sides
4 - 8b + 6bc = 7b add 8b to both sides
4 - 6bc = 15b

If you need further help or clarification email me or im me. Good Luck.

Answer 3

2(1+c)-(2+c)=10
2+2c-2-c=10
2c-c=10
c=10

(2/3)M= M+4
(2/3)M-M= 4
-(1/3)M=4
M= -12

4(5-2b)+3c(2b-1)=7(b+2)
20-8b+3(10)(2b-1)=7b+14
20-8b+60b-30=7b+14
-10+52b=7b+14
52b-7b=24
b= 24/45

Answer 4

2+2c-2-c=10
c=10

2/3M=M+4
multiply all by 3

2M=3M+12
-M=12
M=-12

20-8b+6bc-3c=7b+14
20-14-8b-7b+6bc-3c=0
6-15b+6bc-3c

Answer 5

c= 10
M= -12

c= (15b-6)/(6b-3) = (5b-2)/(2b-1) ...or...
b= (3c-6)/(6c-15) = (3c-6)/((3(2c-5))