how to simplify this problem?

Question

this problem is probably really easy but im drawing a blank on how to do it.please sow the steps thanks

SIMPLIFY:
5x
over
x squared+x-6

multiplyed by

x squared-9
over
25x squared

ok, well im not sure which answer to pick because you guys have given me two different choices.

Answer 1

(5x / x^2 + x - 6) X (x^2 - 9 / 25x^2)

= (5x/25x^2) X [(x^2 - 9) / (x^2 +x - 6)]

= 1/5x X [(x + 3)(x - 3) / (x + 3) (x - 2)]

= (x - 3) / 5x(x - 2)

Answer 2

5x/(x+3)(x-2) * (x-3)(x+3)/25x^2. Cross reduce the 5x & 25x^2. then cross reduce the x+3 out of denominator of 1st fraction & the numerator of 2nd fraction.

You end up w/ before multiplying:
1/x-2 * x-3/5x Now multiply you get:
x-3/5x(x-2) or x-3/5x^2-10

Answer 3

Question: 5x/(x^2 + x - 6) x (x^2 - 9)/25x^2

Answer: 5x(x^2 - 9) / 25x^2(x^2 +x - 9)

This simplifies too;

5x(x+3)(x-3) / 25x^2(x+3)(x-2)

Therefore (x+3) cancels

=> 5x(x-3) / 25x^2(x-2) (5x cancels with 25x^2)

=> (x-3) / 5x(x-2)

=> (x-3) / 5x^2 -10x

Answer 4

Reduces after finding and canceling cross factors, (x-3)/(5x^2-10x)

Answer 5

5x x^2-9( x-3)(x+3)
------- ----------------------------
x^2+x-6 25x^2
(x+3)(x-2)

cancel out x+3 and reduce 5x to 1 and 25x^2 to 5x

1 x-3
x-2 5x

answer x-3/ 5x^2-10x

Answer 6

1
over
x-6

mulitplied by

-9
over
5

I think... that chapter pwned me...