Please HELP!? I am desperate!!?

Question

Let f(x) = (x^2 + 3)^2(x^3 – 2)^3/(4x – 1)^5. Determine f ‘ (x). Leave the derivative in un-simplified form.

Answer 1

This can also be written as...

(x^2 + 3)^2 (x^3 – 2)^3 (4x – 1)^-5

Using the product rule... Take the derivative of one times the other two + the deriviative of the next one times the other two + the derivative of the last one times the other two...

Derivative of (x^2 + 3)^2
= 2(2x)(x^2 + 3)

Derivative of (x^3 – 2)^3
= 3(3x^2)(x^3 - 2)^2

Derivative of (4x – 1)^-5
= (-5)(4)(4x - 1)^-6

So, the final answer is
2(2x)(x^2 + 3)(x^3 – 2)^3 (4x – 1)^-5
+
3(3x^2)(x^3 - 2)^2 (x^2 + 3)^2 (4x – 1)^-5
+
(-5)(4)(4x - 1)^-6 (x^2 + 3)^2 (x^3 – 2)^3

Answer 2

2(2x)(x^2 + 3)(x^3 – 2)^3 (4x – 1)^-5
+
3(3x^2)(x^3 - 2)^2 (x^2 + 3)^2 (4x – 1)^-5
+
(-5)(4)(4x - 1)^-6 (x^2 + 3)^2 (x^3 – 2)^3

You do the work to get there.

Answer 3

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Answer 4

Let me guess..... You and 'slow_math' are in the same class ☺

Doug

Answer 5

You cant figure this out, YOU STUPID!!!