I came up with 17 & 7, but can't put it algebraically.
2007-05-24 07:21:36 · 6 answers · asked by Marcus T 1 in Science & Mathematics ➔ Zoology
he has 2 legs
2007-05-24 17:53:20 · answer #1 · answered by Discohugworm 2 · 0⤊ 0⤋
Let W be cows and H be chickens. Then W+H = 24, and 4W+2H = 62. This solves to W = 7 and H = 17.
2007-05-24 07:26:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Your question is incomplete. It presumes that all the cows have four legs and all the chickens have two. I have known many one-legged chickens although I think a three-legged cow would be a rarity.
2007-05-24 12:12:53 · answer #3 · answered by tentofield 7 · 0⤊ 0⤋
11chickens thats 11x2=22
10 cows thats 10X4 =40
62
2007-05-24 09:42:46 · answer #4 · answered by Jim B 1 · 0⤊ 0⤋
let num of cows = x and num of cows = y.
x + y = 24 therefore y = 24 - x
4x + 2y = 62
substituting gives 4x + 2(24 - x) = 62
4x + 48 - 2x = 62
therefore 2x = 14
x = 7
y = 17
2007-05-24 07:28:50 · answer #5 · answered by CuriousGeorge 1 · 0⤊ 0⤋
Yes that is correct
2007-05-24 07:30:11 · answer #6 · answered by alexr1229 2 · 0⤊ 0⤋