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The sum of three numbers is 90. The largest number is three times the smallest and the smallest is 10 less than the middle number. Find the area of a circle with a diameter equivalent to the middle number.

Here is what I get stuck at
I write out the equation
X+Y+Z =90

X=Y-10
Z = 3X
And then I just cant figure it out from there

2007-05-24 06:28:21 · 5 answers · asked by shawn s 1 in Science & Mathematics Mathematics

5 answers

X+Y+Z =90

X=Y-10
Z = 3X

X + (X+10) + (3X) =90
5X = 80
X = 16

Y = 26
Z = 48

Area = pi * diam = pi * 26

2007-05-24 06:34:49 · answer #1 · answered by fcas80 7 · 0 0

Plug stuff into the initial equation. Y-10+Y+3(y-10)=90
Distribute y-10+y+3y-30=90
Combine like terms 5y-40=90
take the (40) to the other side 5y=130
divide by five y=26
now take that and find the other values.
X=y-10
x=26-10
x=16

Z=3x
z=3(16)
z=48

so you get z=48, x=16, and y=26.

now check it using the info given. the largest is three times the smallest. well 16 times 3 is 48, so thats right. and the smallest is 10 less than the middle number. well 16 is ten less than 26 so thats right.

2007-05-24 06:40:01 · answer #2 · answered by chetzel 3 · 0 0

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2016-11-05 06:17:49 · answer #3 · answered by Anonymous · 0 0

x + y + z = 90
z = 3x so
x + y + 3x = 90
x = y -10
so y = x +10
x + (x + 10) + 3x = 90
5x + 10 = 90
5x = 80
x = 16
y = 26
z = 48

2007-05-24 06:32:20 · answer #4 · answered by TychaBrahe 7 · 1 0

M is middle
M - 10 is smallest
3(M - 10) is largest, and

M + M - 10 + 3(M - 10) = 90
5M - 40 = 90
5M = 130
M = 26
smallest = 16
largest = 48

2007-05-24 06:34:57 · answer #5 · answered by Philo 7 · 0 0

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