Factor completely x^3-x^2-6x
2007-05-24 06:20:04 · 9 answers · asked by babydollof4kids 1 in Education & Reference ➔ Homework Help
x^3-x^2-6x
x(x^2 - x - 6)
x(x - 3)(x + 2)
.
2007-05-24 06:23:13 · answer #1 · answered by Robert L 7 · 0⤊ 0⤋
To begin with, all the parts of your expression will divide by x, which will give you:
x (x^2 -x - 6)
x^2 - x - 6 will factorise again, by inspection. You're looking for two numbers which will multiply to give -6, and add to give -1 (the factor of x). This is +2 and -3
Which means that
x^2 - x - 6 = (x+2)(x-3)
If you're not sure, multiply out (x+2)(x-3) and try it.
This gives the final answer
x^3 - x^2 - 6x = x(x+2)(x-3)
2007-05-24 06:29:35 · answer #2 · answered by Anonymous · 0⤊ 0⤋
equation: x^3-x^2-6x=
factor out "x" : x(x^2-x-6)=
Factor inside (): x(x+2)(x-3)=
Solution!: x= 0, -2, 3
2007-05-24 06:27:52 · answer #3 · answered by tiny_luscioushoney 1 · 0⤊ 0⤋
x(x^2 - x - 6) = x(x-3)(x+2)
2007-05-24 06:26:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋
x^3-x^2-6x
first factor out x
(x)(x^2-x-6)
(x)(x+2)(x-3)
2007-05-24 06:26:00 · answer #5 · answered by math guru 4 · 0⤊ 0⤋
remove the common factor x
u get x(x^2-x-6)
=x(x-3)(x+2)
i hope u know how to factorise x^2-x-6!!
2007-05-24 06:28:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋
well first you can factor one x out, so then you have
x(x^2-x-6)
Then, you can factor the inside which turns out to be
x(x-3)(x+2)
You should multiply this answer out to see that it really works (FOIL it: First, Outer, Inner, Last)
2007-05-24 06:25:47 · answer #7 · answered by ScotOS 2 · 0⤊ 0⤋
x(x^2-x-6)
2007-05-24 06:24:23 · answer #8 · answered by Anonymous · 0⤊ 0⤋
the first answer is correct. What exactly is a babydoll of 4 kids?
2007-05-24 09:26:28 · answer #9 · answered by George C 3 · 0⤊ 0⤋