2007-05-24 04:34:43 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5 and 3 fit this bill. You can do this through the brute force method.
If you want to solve it algebraically, set up an equation. Since the difference of the two factors is 2, you know that you can write them as n and n + 2. As they are factors of 15, you can multiply them together to get:
n(n+2) = 15
Multiply this out and set all the terms on one side. Solve for n:
n^2 + 2n - 15 = 0
(n - 3)(n + 5) = 0
So, n = 3 or n = -5.
If n = 3, then n + 2 = 5, so 3 and 5 are two such factors.
If n = -5, then n + 2 = -3, so -5 and -3 are also two such factors.
If you want only the positive factors, then stick with 3 and 5.
2007-05-24 04:36:50 · answer #1 · answered by Rev Kev 5 · 0⤊ 0⤋
the two factors of 15 are 5 and 3, ignoring 1. And they satisfy the condition of differing by 2. So, 5 and 3 are the two factors.
2007-05-24 11:38:11 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
5 and 3 ?
2007-05-24 11:37:03 · answer #3 · answered by hoang_hiepsi 4 · 0⤊ 0⤋
let the smaller factor be x
=>the other factor is x+2
=>x(x+2)=15
=>x^2 +2x - 15=0
=>x^2 + 5x - 3x - 15=0
=>x(x+5) - 3(x+5)=0
=>(x+5)(x-3)=0
=>x=-5,3
=>other factor is 3+2=5 or -5+2=-3
=(3,5) or (-5,-3)
2007-05-24 11:41:05 · answer #4 · answered by sushant 3 · 1⤊ 0⤋
5(3) = 15
5 - 3 = 2
2007-05-24 11:37:14 · answer #5 · answered by Poetland 6 · 0⤊ 0⤋
factors are just prime numbers. What two prime numbers can you multiply together to get 15?
2007-05-24 11:38:25 · answer #6 · answered by misti 2 · 0⤊ 1⤋
-3,5
3X5=15
5-3=2
2007-05-24 11:37:04 · answer #7 · answered by Anonymous · 0⤊ 1⤋